2x-3(x+1)=2x+2(x+2)

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Solution for 2x-3(x+1)=2x+2(x+2) equation: 



2x-3(x+1)=2x+2(x+2)

We move all terms to the left:

2x-3(x+1)-(2x+2(x+2))=0

We multiply parentheses

2x-3x-(2x+2(x+2))-3=0



We calculate terms in parentheses: -(2x+2(x+2)), so:

2x+2(x+2)

We multiply parentheses

2x+2x+4

We add all the numbers together, and all the variables

4x+4

Back to the equation:

-(4x+4)



We add all the numbers together, and all the variables

-1x-(4x+4)-3=0

We get rid of parentheses

-1x-4x-4-3=0

We add all the numbers together, and all the variables

-5x-7=0

We move all terms containing x to the left, all other terms to the right

-5x=7

x=7/-5

x=-1+2/5

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