2x-3(4-x)=8+4(x-1

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Solution for 2x-3(4-x)=8+4(x-1 equation: 



2x-3(4-x)=8+4(x-1

We move all terms to the left:

2x-3(4-x)-(8+4(x-1)=0

We add all the numbers together, and all the variables

2x-3(-1x+4)-(8+4(x-1)=0

We multiply parentheses

2x+3x-(8+4(x-1)-12=0

We add all the numbers together, and all the variables

5x-(8+4(x-1)-12=0

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