2x-3(3-4x)=4(x-4)-43

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Solution for 2x-3(3-4x)=4(x-4)-43 equation: 



2x-3(3-4x)=4(x-4)-43

We move all terms to the left:

2x-3(3-4x)-(4(x-4)-43)=0

We add all the numbers together, and all the variables

2x-3(-4x+3)-(4(x-4)-43)=0

We multiply parentheses

2x+12x-(4(x-4)-43)-9=0



We calculate terms in parentheses: -(4(x-4)-43), so:

4(x-4)-43

We multiply parentheses

4x-16-43

We add all the numbers together, and all the variables

4x-59

Back to the equation:

-(4x-59)



We add all the numbers together, and all the variables

14x-(4x-59)-9=0

We get rid of parentheses

14x-4x+59-9=0

We add all the numbers together, and all the variables

10x+50=0

We move all terms containing x to the left, all other terms to the right

10x=-50

x=-50/10

x=-5

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