2x-3(2x-5)=5-4(2-3x)

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Solution for 2x-3(2x-5)=5-4(2-3x) equation: 



2x-3(2x-5)=5-4(2-3x)

We move all terms to the left:

2x-3(2x-5)-(5-4(2-3x))=0

We add all the numbers together, and all the variables

2x-3(2x-5)-(5-4(-3x+2))=0

We multiply parentheses

2x-6x-(5-4(-3x+2))+15=0



We calculate terms in parentheses: -(5-4(-3x+2)), so:

5-4(-3x+2)

determiningTheFunctionDomain
-4(-3x+2)+5

We multiply parentheses

12x-8+5

We add all the numbers together, and all the variables

12x-3

Back to the equation:

-(12x-3)



We add all the numbers together, and all the variables

-4x-(12x-3)+15=0

We get rid of parentheses

-4x-12x+3+15=0

We add all the numbers together, and all the variables

-16x+18=0

We move all terms containing x to the left, all other terms to the right

-16x=-18

x=-18/-16

x=1+1/8

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