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2x-3(2x-4)=5x+22-10x
We move all terms to the left:
2x-3(2x-4)-(5x+22-10x)=0
We add all the numbers together, and all the variables
2x-3(2x-4)-(-5x+22)=0
We multiply parentheses
2x-6x-(-5x+22)+12=0
We get rid of parentheses
2x-6x+5x-22+12=0
We add all the numbers together, and all the variables
x-10=0
We move all terms containing x to the left, all other terms to the right
x=10
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