2x-3(2-3x)=4(x-5)-0

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Solution for 2x-3(2-3x)=4(x-5)-0 equation: 



2x-3(2-3x)=4(x-5)-0

We move all terms to the left:

2x-3(2-3x)-(4(x-5)-0)=0

We add all the numbers together, and all the variables

2x-3(-3x+2)-(4(x-5)-0)=0

We multiply parentheses

2x+9x-(4(x-5)-0)-6=0



We calculate terms in parentheses: -(4(x-5)-0), so:

4(x-5)-0

We add all the numbers together, and all the variables

4(x-5)

We multiply parentheses

4x-20

Back to the equation:

-(4x-20)



We add all the numbers together, and all the variables

11x-(4x-20)-6=0

We get rid of parentheses

11x-4x+20-6=0

We add all the numbers together, and all the variables

7x+14=0

We move all terms containing x to the left, all other terms to the right

7x=-14

x=-14/7

x=-2

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