2x-3(1-x)=3(x-4)-5

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Solution for 2x-3(1-x)=3(x-4)-5 equation: 



2x-3(1-x)=3(x-4)-5

We move all terms to the left:

2x-3(1-x)-(3(x-4)-5)=0

We add all the numbers together, and all the variables

2x-3(-1x+1)-(3(x-4)-5)=0

We multiply parentheses

2x+3x-(3(x-4)-5)-3=0



We calculate terms in parentheses: -(3(x-4)-5), so:

3(x-4)-5

We multiply parentheses

3x-12-5

We add all the numbers together, and all the variables

3x-17

Back to the equation:

-(3x-17)



We add all the numbers together, and all the variables

5x-(3x-17)-3=0

We get rid of parentheses

5x-3x+17-3=0

We add all the numbers together, and all the variables

2x+14=0

We move all terms containing x to the left, all other terms to the right

2x=-14

x=-14/2

x=-7

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