If it's not what You are looking for type in the equation solver your own equation and let us solve it.
2x-2=5/3x-5
We move all terms to the left:
2x-2-(5/3x-5)=0
Domain of the equation: 3x-5)!=0We get rid of parentheses
x∈R
2x-5/3x+5-2=0
We multiply all the terms by the denominator
2x*3x+5*3x-2*3x-5=0
Wy multiply elements
6x^2+15x-6x-5=0
We add all the numbers together, and all the variables
6x^2+9x-5=0
a = 6; b = 9; c = -5;
Δ = b2-4ac
Δ = 92-4·6·(-5)
Δ = 201
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{201}}{2*6}=\frac{-9-\sqrt{201}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{201}}{2*6}=\frac{-9+\sqrt{201}}{12} $
| 2x-2=(5/3x)-5 | | x3+4x2+-1x+-4=0 | | -x-9=6+2x | | 5a+8-17a+4=3a+12-5a | | 61=x2-3 | | 3/5=6/3+x | | 6y+5=51 | | 4·(x+5)=2x+26 | | 4y+2=-7+y | | 3y+y=5+y | | 5y+y=5+y | | x²-12x+20=0 | | 15+d=-6 | | 2(10x+3=11 | | y+1.8=3.2 | | 5(2x+-1=40 | | 5x+6=3×+7 | | 5(2x-1=40 | | (x+2)(x-2)+(x-1)^2=x-3 | | -1+1/3x=-3/5 | | -0,6(4x-0,5)-0,8=0,5(5x-18,6) | | 3(3x+2)=24# | | 3(3x+2)=27 | | 9/7=9/2p | | 2(2x+3=10 | | 24x-3x=5.5 | | 8x-3x=18-3 | | 2x+10=2(2x-5) | | 93-10x=3 | | 2x-0.8=1.2 | | 5x–(3+2x)=3 | | 68-x=44 |