2x-2+2(3x+2)=-4(x+1)

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Solution for 2x-2+2(3x+2)=-4(x+1) equation: 



2x-2+2(3x+2)=-4(x+1)

We move all terms to the left:

2x-2+2(3x+2)-(-4(x+1))=0

We multiply parentheses

2x+6x-(-4(x+1))+4-2=0



We calculate terms in parentheses: -(-4(x+1)), so:

-4(x+1)

We multiply parentheses

-4x-4

Back to the equation:

-(-4x-4)



We add all the numbers together, and all the variables

8x-(-4x-4)+2=0

We get rid of parentheses

8x+4x+4+2=0

We add all the numbers together, and all the variables

12x+6=0

We move all terms containing x to the left, all other terms to the right

12x=-6

x=-6/12

x=-1/2

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