2x-2+2(3x+2)=-2(x+3)

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Solution for 2x-2+2(3x+2)=-2(x+3) equation: 



2x-2+2(3x+2)=-2(x+3)

We move all terms to the left:

2x-2+2(3x+2)-(-2(x+3))=0

We multiply parentheses

2x+6x-(-2(x+3))+4-2=0



We calculate terms in parentheses: -(-2(x+3)), so:

-2(x+3)

We multiply parentheses

-2x-6

Back to the equation:

-(-2x-6)



We add all the numbers together, and all the variables

8x-(-2x-6)+2=0

We get rid of parentheses

8x+2x+6+2=0

We add all the numbers together, and all the variables

10x+8=0

We move all terms containing x to the left, all other terms to the right

10x=-8

x=-8/10

x=-4/5

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