2x-2(4x+3)=6x+19

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Solution for 2x-2(4x+3)=6x+19 equation:



2x-2(4x+3)=6x+19
We move all terms to the left:
2x-2(4x+3)-(6x+19)=0
We multiply parentheses
2x-8x-(6x+19)-6=0
We get rid of parentheses
2x-8x-6x-19-6=0
We add all the numbers together, and all the variables
-12x-25=0
We move all terms containing x to the left, all other terms to the right
-12x=25
x=25/-12
x=-2+1/12

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