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2x-2(-1/3x+5=-2
We move all terms to the left:
2x-2(-1/3x+5-(-2)=0
Domain of the equation: 3x+5-(-2)!=0We multiply all the terms by the denominator
We move all terms containing x to the left, all other terms to the right
3x-(-2)!=-5
x∈R
2x*3x+5-(-2)-2(-1=0
We add all the numbers together, and all the variables
2x*3x=0
Wy multiply elements
6x^2=0
a = 6; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·6·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{12}=0$
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