2x-1=5(x+1)-3(x+2)

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Solution for 2x-1=5(x+1)-3(x+2) equation: 



2x-1=5(x+1)-3(x+2)

We move all terms to the left:

2x-1-(5(x+1)-3(x+2))=0



We calculate terms in parentheses: -(5(x+1)-3(x+2)), so:

5(x+1)-3(x+2)

We multiply parentheses

5x-3x+5-6

We add all the numbers together, and all the variables

2x-1

Back to the equation:

-(2x-1)



We get rid of parentheses

2x-2x+1-1=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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