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2x-12=3-3(x-5)
We move all terms to the left:
2x-12-(3-3(x-5))=0
We calculate terms in parentheses: -(3-3(x-5)), so:We get rid of parentheses
3-3(x-5)
determiningTheFunctionDomain -3(x-5)+3
We multiply parentheses
-3x+15+3
We add all the numbers together, and all the variables
-3x+18
Back to the equation:
-(-3x+18)
2x+3x-18-12=0
We add all the numbers together, and all the variables
5x-30=0
We move all terms containing x to the left, all other terms to the right
5x=30
x=30/5
x=6
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