2x-128-10x=56

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Solution for 2x-128-10x=56 equation: 



2x-128-10x=56

We move all terms to the left:

2x-128-10x-(56)=0

We add all the numbers together, and all the variables

-8x-184=0

We move all terms containing x to the left, all other terms to the right

-8x=184

x=184/-8

x=-23

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