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2x-11/7x=3
We move all terms to the left:
2x-11/7x-(3)=0
Domain of the equation: 7x!=0We multiply all the terms by the denominator
x!=0/7
x!=0
x∈R
2x*7x-3*7x-11=0
Wy multiply elements
14x^2-21x-11=0
a = 14; b = -21; c = -11;
Δ = b2-4ac
Δ = -212-4·14·(-11)
Δ = 1057
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-21)-\sqrt{1057}}{2*14}=\frac{21-\sqrt{1057}}{28} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-21)+\sqrt{1057}}{2*14}=\frac{21+\sqrt{1057}}{28} $
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