2x-10=2(x-35)+(x-10)

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Solution for 2x-10=2(x-35)+(x-10) equation: 



2x-10=2(x-35)+(x-10)

We move all terms to the left:

2x-10-(2(x-35)+(x-10))=0



We calculate terms in parentheses: -(2(x-35)+(x-10)), so:

2(x-35)+(x-10)

We multiply parentheses

2x+(x-10)-70

We get rid of parentheses

2x+x-10-70

We add all the numbers together, and all the variables

3x-80

Back to the equation:

-(3x-80)



We get rid of parentheses

2x-3x+80-10=0

We add all the numbers together, and all the variables

-1x+70=0

We move all terms containing x to the left, all other terms to the right

-x=-70

x=-70/-1

x=+70

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