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2x-10/x=12
We move all terms to the left:
2x-10/x-(12)=0
Domain of the equation: x!=0We multiply all the terms by the denominator
x∈R
2x*x-12*x-10=0
We add all the numbers together, and all the variables
-12x+2x*x-10=0
Wy multiply elements
2x^2-12x-10=0
a = 2; b = -12; c = -10;
Δ = b2-4ac
Δ = -122-4·2·(-10)
Δ = 224
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{224}=\sqrt{16*14}=\sqrt{16}*\sqrt{14}=4\sqrt{14}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-4\sqrt{14}}{2*2}=\frac{12-4\sqrt{14}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+4\sqrt{14}}{2*2}=\frac{12+4\sqrt{14}}{4} $
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