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2x-1/x+2=x+1/x-3
We move all terms to the left:
2x-1/x+2-(x+1/x-3)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: x-3)!=0We get rid of parentheses
x∈R
2x-1/x-x-1/x+3+2=0
We multiply all the terms by the denominator
2x*x-x*x+3*x+2*x-1-1=0
We add all the numbers together, and all the variables
5x+2x*x-x*x-2=0
Wy multiply elements
2x^2-1x^2+5x-2=0
We add all the numbers together, and all the variables
x^2+5x-2=0
a = 1; b = 5; c = -2;
Δ = b2-4ac
Δ = 52-4·1·(-2)
Δ = 33
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{33}}{2*1}=\frac{-5-\sqrt{33}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{33}}{2*1}=\frac{-5+\sqrt{33}}{2} $
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