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2x-1/3x=12
We move all terms to the left:
2x-1/3x-(12)=0
Domain of the equation: 3x!=0We multiply all the terms by the denominator
x!=0/3
x!=0
x∈R
2x*3x-12*3x-1=0
Wy multiply elements
6x^2-36x-1=0
a = 6; b = -36; c = -1;
Δ = b2-4ac
Δ = -362-4·6·(-1)
Δ = 1320
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1320}=\sqrt{4*330}=\sqrt{4}*\sqrt{330}=2\sqrt{330}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-2\sqrt{330}}{2*6}=\frac{36-2\sqrt{330}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+2\sqrt{330}}{2*6}=\frac{36+2\sqrt{330}}{12} $
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