2x-1/3x+5=5

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Solution for 2x-1/3x+5=5 equation:



2x-1/3x+5=5
We move all terms to the left:
2x-1/3x+5-(5)=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
We add all the numbers together, and all the variables
2x-1/3x=0
We multiply all the terms by the denominator
2x*3x-1=0
Wy multiply elements
6x^2-1=0
a = 6; b = 0; c = -1;
Δ = b2-4ac
Δ = 02-4·6·(-1)
Δ = 24
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{24}=\sqrt{4*6}=\sqrt{4}*\sqrt{6}=2\sqrt{6}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{6}}{2*6}=\frac{0-2\sqrt{6}}{12} =-\frac{2\sqrt{6}}{12} =-\frac{\sqrt{6}}{6} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{6}}{2*6}=\frac{0+2\sqrt{6}}{12} =\frac{2\sqrt{6}}{12} =\frac{\sqrt{6}}{6} $

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