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2x-1/2x=120
We move all terms to the left:
2x-1/2x-(120)=0
Domain of the equation: 2x!=0We multiply all the terms by the denominator
x!=0/2
x!=0
x∈R
2x*2x-120*2x-1=0
Wy multiply elements
4x^2-240x-1=0
a = 4; b = -240; c = -1;
Δ = b2-4ac
Δ = -2402-4·4·(-1)
Δ = 57616
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{57616}=\sqrt{16*3601}=\sqrt{16}*\sqrt{3601}=4\sqrt{3601}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-240)-4\sqrt{3601}}{2*4}=\frac{240-4\sqrt{3601}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-240)+4\sqrt{3601}}{2*4}=\frac{240+4\sqrt{3601}}{8} $
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