2x-1+4-(x-x-2)=x+2-(-3x+2-1)

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Solution for 2x-1+4-(x-x-2)=x+2-(-3x+2-1) equation: 



2x-1+4-(x-x-2)=x+2-(-3x+2-1)

We move all terms to the left:

2x-1+4-(x-x-2)-(x+2-(-3x+2-1))=0

We add all the numbers together, and all the variables

2x-(x+2-(-3x+1))-1+4-(-2)=0

We add all the numbers together, and all the variables

2x-(x+2-(-3x+1))+5=0



We calculate terms in parentheses: -(x+2-(-3x+1)), so:

x+2-(-3x+1)

determiningTheFunctionDomain
x-(-3x+1)+2

We get rid of parentheses

x+3x-1+2

We add all the numbers together, and all the variables

4x+1

Back to the equation:

-(4x+1)



We get rid of parentheses

2x-4x-1+5=0

We add all the numbers together, and all the variables

-2x+4=0

We move all terms containing x to the left, all other terms to the right

-2x=-4

x=-4/-2

x=+2

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