2x-1(5x-9)=7+1(x-2)

Simple and best practice solution for 2x-1(5x-9)=7+1(x-2) equation. Check how easy it is, and learn it for the future. Our solution is simple, and easy to understand, so don`t hesitate to use it as a solution of your homework.

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Solution for 2x-1(5x-9)=7+1(x-2) equation: 



2x-1(5x-9)=7+1(x-2)

We move all terms to the left:

2x-1(5x-9)-(7+1(x-2))=0



We calculate terms in parentheses: -(7+1(x-2)), so:

7+1(x-2)

determiningTheFunctionDomain
1(x-2)+7

Back to the equation:

-(1(x-2)+7)





We calculate terms in parentheses: -(1(x-2)+7), so:

1(x-2)+7





We calculate terms in parentheses: -(1(x-2)+7), so:

1(x-2)+7





We calculate terms in parentheses: -(1(x-2)+7), so:

1(x-2)+7





We calculate terms in parentheses: -(1(x-2)+7), so:

1(x-2)+7





We calculate terms in parentheses: -(1(x-2)+7), so:

1(x-2)+7





We calculate terms in parentheses: -(1(x-2)+7), so:

1(x-2)+7





We calculate terms in parentheses: -(1(x-2)+7), so:

1(x-2)+7





We calculate terms in parentheses: -(1(x-2)+7), so:

1(x-2)+7





We calculate terms in parentheses: -(1(x-2)+7), so:

1(x-2)+7





We calculate terms in parentheses: -(1(x-2)+7), so:

1(x-2)+7





We calculate terms in parentheses: -(1(x-2)+7), so:

1(x-2)+7





We calculate terms in parentheses: -(1(x-2)+7), so:

1(x-2)+7





We calculate terms in parentheses: -(1(x-2)+7), so:

1(x-2)+7





We calculate terms in parentheses: -(1(x-2)+7), so:

1(x-2)+7





We calculate terms in parentheses: -(1(x-2)+7), so:

1(x-2)+7





We calculate terms in parentheses: -(1(x-2)+7), so:

1(x-2)+7





We calculate terms in parentheses: -(1(x-2)+7), so:

1(x-2)+7





We calculate terms in parentheses: -(1(x-2)+7), so:

1(x-2)+7





We calculate terms in parentheses: -(1(x-2)+7), so:

1(x-2)+7





We calculate terms in parentheses: -(1(x-2)+7), so:

1(x-2)+7





We calculate terms in parentheses: -(1(x-2)+7), so:

1(x-2)+7





We calculate terms in parentheses: -(1(x-2)+7), so:

1(x-2)+7





We calculate terms in parentheses: -(1(x-2)+7), so:

1(x-2)+7





We calculate terms in parentheses: -(1(x-2)+7), so:

1(x-2)+7





We calculate terms in parentheses: -(1(x-2)+7), so:

1(x-2)+7





We calculate terms in parentheses: -(1(x-2)+7), so:

1(x-2)+7





We calculate terms in parentheses: -(1(x-2)+7), so:

1(x-2)+7





We calculate terms in parentheses: -(1(x-2)+7), so:

1(x-2)+7





We calculate terms in parentheses: -(1(x-2)+7), so:

1(x-2)+7





We calculate terms in parentheses: -(1(x-2)+7), so:

1(x-2)+7





We calculate terms in parentheses: -(1(x-2)+7), so:

1(x-2)+7





We calculate terms in parentheses: -(1(x-2)+7), so:

1(x-2)+7





We calculate terms in parentheses: -(1(x-2)+7), so:

1(x-2)+7





We calculate terms in parentheses: -(1(x-2)+7), so:

1(x-2)+7





We calculate terms in parentheses: -(1(x-2)+7), so:

1(x-2)+7





We calculate terms in parentheses: -(1(x-2)+7), so:

1(x-2)+7





We calculate terms in parentheses: -(1(x-2)+7), so:

1(x-2)+7





We calculate terms in parentheses: -(1(x-2)+7), so:

1(x-2)+7





We calculate terms in parentheses: -(1(x-2)+7), so:

1(x-2)+7





We calculate terms in parentheses: -(1(x-2)+7), so:

1(x-2)+7





We calculate terms in parentheses: -(1(x-2)+7), so:

1(x-2)+7





We calculate terms in parentheses: -(1(x-2)+7), so:

1(x-2)+7





We calculate terms in parentheses: -(1(x-2)+7), so:

1(x-2)+7





We calculate terms in parentheses: -(1(x-2)+7), so:

1(x-2)+7





We calculate terms in parentheses: -(1(x-2)+7), so:

1(x-2)+7





We calculate terms in parentheses: -(1(x-2)+7), so:

1(x-2)+7





We calculate terms in parentheses: -(1(x-2)+7), so:

1(x-2)+7





We calculate terms in parentheses: -(1(x-2)+7), so:

1(x-2)+7





							

									
									
									
									
									
									

														
			

			
				

						
				
				
					
			
						
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