2x-(x+9)=3(x-2)+9

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Solution for 2x-(x+9)=3(x-2)+9 equation: 



2x-(x+9)=3(x-2)+9

We move all terms to the left:

2x-(x+9)-(3(x-2)+9)=0

We get rid of parentheses

2x-x-(3(x-2)+9)-9=0



We calculate terms in parentheses: -(3(x-2)+9), so:

3(x-2)+9

We multiply parentheses

3x-6+9

We add all the numbers together, and all the variables

3x+3

Back to the equation:

-(3x+3)



We add all the numbers together, and all the variables

x-(3x+3)-9=0

We get rid of parentheses

x-3x-3-9=0

We add all the numbers together, and all the variables

-2x-12=0

We move all terms containing x to the left, all other terms to the right

-2x=12

x=12/-2

x=-6

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