2x-(7-5x)/9x-(3+4x=7/6

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Solution for 2x-(7-5x)/9x-(3+4x=7/6 equation: 



2x-(7-5x)/9x-(3+4x=7/6

We move all terms to the left:

2x-(7-5x)/9x-(3+4x-(7/6)=0



Domain of the equation: 9x!=0

x!=0/9

x!=0

x∈R



We add all the numbers together, and all the variables

2x-(-5x+7)/9x-(3+4x-(+7/6)=0

We calculate fractions


2x+5x/54x^2+(-(3+4x-(+7*9x)/54x^2=0

We multiply all the terms by the denominator


2x*54x^2+5x+(-(3+4x-(+7*9x)=0



We calculate terms in parentheses: +(-(3+4x-(+7*9x), so:

-(3+4x-(+7*9x



We add all the numbers together, and all the variables

5x+2x*54x^2+(-(3+4x-(+7*9x)=0

Wy multiply elements

108x^3+5x+(-(3+4x-(+7*9x)=0



We calculate terms in parentheses: +(-(3+4x-(+7*9x), so:

-(3+4x-(+7*9x



We do not support expression: x^3

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