2x-(5x-(6x+2))=14-x

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Solution for 2x-(5x-(6x+2))=14-x equation: 



2x-(5x-(6x+2))=14-x

We move all terms to the left:

2x-(5x-(6x+2))-(14-x)=0

We add all the numbers together, and all the variables

2x-(5x-(6x+2))-(-1x+14)=0

We get rid of parentheses

2x-(5x-(6x+2))+1x-14=0



We calculate terms in parentheses: -(5x-(6x+2)), so:

5x-(6x+2)

We get rid of parentheses

5x-6x-2

We add all the numbers together, and all the variables

-1x-2

Back to the equation:

-(-1x-2)



We add all the numbers together, and all the variables

3x-(-1x-2)-14=0

We get rid of parentheses

3x+1x+2-14=0

We add all the numbers together, and all the variables

4x-12=0

We move all terms containing x to the left, all other terms to the right

4x=12

x=12/4

x=3

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