2x-(3x-4)-(x+5)-8=19

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Solution for 2x-(3x-4)-(x+5)-8=19 equation: 



2x-(3x-4)-(x+5)-8=19

We move all terms to the left:

2x-(3x-4)-(x+5)-8-(19)=0

We add all the numbers together, and all the variables

2x-(3x-4)-(x+5)-27=0

We get rid of parentheses

2x-3x-x+4-5-27=0

We add all the numbers together, and all the variables

-2x-28=0

We move all terms containing x to the left, all other terms to the right

-2x=28

x=28/-2

x=-14

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