2x-(3x-2)=2(x-2)+20

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Solution for 2x-(3x-2)=2(x-2)+20 equation: 



2x-(3x-2)=2(x-2)+20

We move all terms to the left:

2x-(3x-2)-(2(x-2)+20)=0

We get rid of parentheses

2x-3x-(2(x-2)+20)+2=0



We calculate terms in parentheses: -(2(x-2)+20), so:

2(x-2)+20

We multiply parentheses

2x-4+20

We add all the numbers together, and all the variables

2x+16

Back to the equation:

-(2x+16)



We add all the numbers together, and all the variables

-1x-(2x+16)+2=0

We get rid of parentheses

-1x-2x-16+2=0

We add all the numbers together, and all the variables

-3x-14=0

We move all terms containing x to the left, all other terms to the right

-3x=14

x=14/-3

x=-4+2/3

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