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2x-(3x+4)+6x(2x-7)=-4+2x
We move all terms to the left:
2x-(3x+4)+6x(2x-7)-(-4+2x)=0
We add all the numbers together, and all the variables
2x-(3x+4)+6x(2x-7)-(2x-4)=0
We multiply parentheses
12x^2+2x-(3x+4)-42x-(2x-4)=0
We get rid of parentheses
12x^2+2x-3x-42x-2x-4+4=0
We add all the numbers together, and all the variables
12x^2-45x=0
a = 12; b = -45; c = 0;
Δ = b2-4ac
Δ = -452-4·12·0
Δ = 2025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2025}=45$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-45)-45}{2*12}=\frac{0}{24} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-45)+45}{2*12}=\frac{90}{24} =3+3/4 $
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