2x-(3x+)=2x-18

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Solution for 2x-(3x+)=2x-18 equation: 



2x-(3x+)=2x-18

We move all terms to the left:

2x-(3x+)-(2x-18)=0

We add all the numbers together, and all the variables

2x-(+3x)-(2x-18)=0

We get rid of parentheses

2x-3x-2x+18=0

We add all the numbers together, and all the variables

-3x+18=0

We move all terms containing x to the left, all other terms to the right

-3x=-18

x=-18/-3

x=+6

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