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2x+x-2=3(4-3x)
We move all terms to the left:
2x+x-2-(3(4-3x))=0
We add all the numbers together, and all the variables
2x+x-(3(-3x+4))-2=0
We add all the numbers together, and all the variables
3x-(3(-3x+4))-2=0
We calculate terms in parentheses: -(3(-3x+4)), so:We get rid of parentheses
3(-3x+4)
We multiply parentheses
-9x+12
Back to the equation:
-(-9x+12)
3x+9x-12-2=0
We add all the numbers together, and all the variables
12x-14=0
We move all terms containing x to the left, all other terms to the right
12x=14
x=14/12
x=1+1/6
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