2x+9x-(x-1)=8(2x+2)-5

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Solution for 2x+9x-(x-1)=8(2x+2)-5 equation: 



2x+9x-(x-1)=8(2x+2)-5

We move all terms to the left:

2x+9x-(x-1)-(8(2x+2)-5)=0

We add all the numbers together, and all the variables

11x-(x-1)-(8(2x+2)-5)=0

We get rid of parentheses

11x-x-(8(2x+2)-5)+1=0



We calculate terms in parentheses: -(8(2x+2)-5), so:

8(2x+2)-5

We multiply parentheses

16x+16-5

We add all the numbers together, and all the variables

16x+11

Back to the equation:

-(16x+11)



We add all the numbers together, and all the variables

10x-(16x+11)+1=0

We get rid of parentheses

10x-16x-11+1=0

We add all the numbers together, and all the variables

-6x-10=0

We move all terms containing x to the left, all other terms to the right

-6x=10

x=10/-6

x=-1+2/3

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