2x+9/x-3=5

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Solution for 2x+9/x-3=5 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

2*x+9/x-3 = 5 // - 5

2*x+9/x-5-3 = 0

2*x^1+9*x^-1-8*x^0 = 0

(2*x^2-8*x^1+9*x^0)/(x^1) = 0 // * x^2

x^1*(2*x^2-8*x^1+9*x^0) = 0

x^1

2*x^2-8*x+9 = 0

2*x^2-8*x+9 = 0

DELTA = (-8)^2-(2*4*9)

DELTA = -8

DELTA < 0

x in { } 

x belongs to the empty set

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