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2x+8/5x-4=82
We move all terms to the left:
2x+8/5x-4-(82)=0
Domain of the equation: 5x!=0We add all the numbers together, and all the variables
x!=0/5
x!=0
x∈R
2x+8/5x-86=0
We multiply all the terms by the denominator
2x*5x-86*5x+8=0
Wy multiply elements
10x^2-430x+8=0
a = 10; b = -430; c = +8;
Δ = b2-4ac
Δ = -4302-4·10·8
Δ = 184580
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{184580}=\sqrt{4*46145}=\sqrt{4}*\sqrt{46145}=2\sqrt{46145}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-430)-2\sqrt{46145}}{2*10}=\frac{430-2\sqrt{46145}}{20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-430)+2\sqrt{46145}}{2*10}=\frac{430+2\sqrt{46145}}{20} $
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