2x+8+3x=3(2x-4)+2

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Solution for 2x+8+3x=3(2x-4)+2 equation: 



2x+8+3x=3(2x-4)+2

We move all terms to the left:

2x+8+3x-(3(2x-4)+2)=0

We add all the numbers together, and all the variables

5x-(3(2x-4)+2)+8=0



We calculate terms in parentheses: -(3(2x-4)+2), so:

3(2x-4)+2

We multiply parentheses

6x-12+2

We add all the numbers together, and all the variables

6x-10

Back to the equation:

-(6x-10)



We get rid of parentheses

5x-6x+10+8=0

We add all the numbers together, and all the variables

-1x+18=0

We move all terms containing x to the left, all other terms to the right

-x=-18

x=-18/-1

x=+18

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