2x+8(6x-7)=2+4(8x-12)

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Solution for 2x+8(6x-7)=2+4(8x-12) equation: 



2x+8(6x-7)=2+4(8x-12)

We move all terms to the left:

2x+8(6x-7)-(2+4(8x-12))=0

We multiply parentheses

2x+48x-(2+4(8x-12))-56=0



We calculate terms in parentheses: -(2+4(8x-12)), so:

2+4(8x-12)

determiningTheFunctionDomain
4(8x-12)+2

We multiply parentheses

32x-48+2

We add all the numbers together, and all the variables

32x-46

Back to the equation:

-(32x-46)



We add all the numbers together, and all the variables

50x-(32x-46)-56=0

We get rid of parentheses

50x-32x+46-56=0

We add all the numbers together, and all the variables

18x-10=0

We move all terms containing x to the left, all other terms to the right

18x=10

x=10/18

x=5/9

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