2x+7x-9=3(3x-2)-3

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Solution for 2x+7x-9=3(3x-2)-3 equation: 



2x+7x-9=3(3x-2)-3

We move all terms to the left:

2x+7x-9-(3(3x-2)-3)=0

We add all the numbers together, and all the variables

9x-(3(3x-2)-3)-9=0



We calculate terms in parentheses: -(3(3x-2)-3), so:

3(3x-2)-3

We multiply parentheses

9x-6-3

We add all the numbers together, and all the variables

9x-9

Back to the equation:

-(9x-9)



We get rid of parentheses

9x-9x+9-9=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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