2x+7=0+3/5x

Solution for 2x+7=0+3/5x equation:

2x+7=0+3/5x

We move all terms to the left:

2x+7-(0+3/5x)=0


Domain of the equation: 5x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

2x-(+3/5x)+7=0

We get rid of parentheses

2x-3/5x+7=0

We multiply all the terms by the denominator


2x*5x+7*5x-3=0

Wy multiply elements

10x^2+35x-3=0

a = 10; b = 35; c = -3;
Δ = b2-4ac
Δ = 352-4·10·(-3)
Δ = 1345
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-\sqrt{1345}}{2*10}=\frac{-35-\sqrt{1345}}{20}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+\sqrt{1345}}{2*10}=\frac{-35+\sqrt{1345}}{20}
$