2x+6=(2/3)2x-1

Solution for 2x+6=(2/3)2x-1 equation:

2x+6=(2/3)2x-1

We move all terms to the left:

2x+6-((2/3)2x-1)=0


Domain of the equation: 3)2x-1)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

2x-((+2/3)2x-1)+6=0

We multiply all the terms by the denominator


2x*3)2x-1)-((+6*3)2x-1)+2=0

We add all the numbers together, and all the variables

2x*3)2x-1)-(182x-1)+2=0

Wy multiply elements

6x^2=0

a = 6; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·6·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{12}=0$