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2x+6=(-1/5x)+3
We move all terms to the left:
2x+6-((-1/5x)+3)=0
Domain of the equation: 5x)+3)!=0We multiply all the terms by the denominator
x!=0/1
x!=0
x∈R
2x*5x)+3)-((+6*5x)+3)-1=0
Wy multiply elements
10x^2+30x=0
a = 10; b = 30; c = 0;
Δ = b2-4ac
Δ = 302-4·10·0
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{900}=30$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-30}{2*10}=\frac{-60}{20} =-3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+30}{2*10}=\frac{0}{20} =0 $
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