2x+50=2x(x+10)

Solution for 2x+50=2x(x+10) equation:

2x+50=2x(x+10)

We move all terms to the left:

2x+50-(2x(x+10))=0


We calculate terms in parentheses: -(2x(x+10)), so:

2x(x+10)

We multiply parentheses

2x^2+20x

Back to the equation:

-(2x^2+20x)


We get rid of parentheses

-2x^2+2x-20x+50=0

We add all the numbers together, and all the variables

-2x^2-18x+50=0

a = -2; b = -18; c = +50;
Δ = b2-4ac
Δ = -182-4·(-2)·50
Δ = 724
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{724}=\sqrt{4*181}=\sqrt{4}*\sqrt{181}=2\sqrt{181}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-2\sqrt{181}}{2*-2}=\frac{18-2\sqrt{181}}{-4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+2\sqrt{181}}{2*-2}=\frac{18+2\sqrt{181}}{-4}
$