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2x+5-5x-4=6-2(x-3)
We move all terms to the left:
2x+5-5x-4-(6-2(x-3))=0
We add all the numbers together, and all the variables
-3x-(6-2(x-3))+1=0
We calculate terms in parentheses: -(6-2(x-3)), so:We get rid of parentheses
6-2(x-3)
determiningTheFunctionDomain -2(x-3)+6
We multiply parentheses
-2x+6+6
We add all the numbers together, and all the variables
-2x+12
Back to the equation:
-(-2x+12)
-3x+2x-12+1=0
We add all the numbers together, and all the variables
-1x-11=0
We move all terms containing x to the left, all other terms to the right
-x=11
x=11/-1
x=-11
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