2x+5-4(3x-2)=2(x-1)

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Solution for 2x+5-4(3x-2)=2(x-1) equation: 



2x+5-4(3x-2)=2(x-1)

We move all terms to the left:

2x+5-4(3x-2)-(2(x-1))=0

We multiply parentheses

2x-12x-(2(x-1))+8+5=0



We calculate terms in parentheses: -(2(x-1)), so:

2(x-1)

We multiply parentheses

2x-2

Back to the equation:

-(2x-2)



We add all the numbers together, and all the variables

-10x-(2x-2)+13=0

We get rid of parentheses

-10x-2x+2+13=0

We add all the numbers together, and all the variables

-12x+15=0

We move all terms containing x to the left, all other terms to the right

-12x=-15

x=-15/-12

x=1+1/4

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