2x+5(3x/2)=19

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Solution for 2x+5(3x/2)=19 equation: 



2x+5(3x/2)=19

We move all terms to the left:

2x+5(3x/2)-(19)=0

We add all the numbers together, and all the variables

2x+5(+3x/2)-19=0

We multiply parentheses

2x+15x-19=0

We add all the numbers together, and all the variables

17x-19=0

We move all terms containing x to the left, all other terms to the right

17x=19

x=19/17

x=1+2/17

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