2x+5(3x-2)=41

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Solution for 2x+5(3x-2)=41 equation: 



2x+5(3x-2)=41

We move all terms to the left:

2x+5(3x-2)-(41)=0

We multiply parentheses

2x+15x-10-41=0

We add all the numbers together, and all the variables

17x-51=0

We move all terms containing x to the left, all other terms to the right

17x=51

x=51/17

x=3

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