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2x+5(10+2/5x)=50
We move all terms to the left:
2x+5(10+2/5x)-(50)=0
Domain of the equation: 5x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
2x+5(2/5x+10)-50=0
We multiply parentheses
2x+10x+50-50=0
We add all the numbers together, and all the variables
12x=0
x=0/12
x=0
Równanie nie ma rozwiązania
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