2x+5(1-x)=-3(x+2)+11

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Solution for 2x+5(1-x)=-3(x+2)+11 equation: 



2x+5(1-x)=-3(x+2)+11

We move all terms to the left:

2x+5(1-x)-(-3(x+2)+11)=0

We add all the numbers together, and all the variables

2x+5(-1x+1)-(-3(x+2)+11)=0

We multiply parentheses

2x-5x-(-3(x+2)+11)+5=0



We calculate terms in parentheses: -(-3(x+2)+11), so:

-3(x+2)+11

We multiply parentheses

-3x-6+11

We add all the numbers together, and all the variables

-3x+5

Back to the equation:

-(-3x+5)



We add all the numbers together, and all the variables

-3x-(-3x+5)+5=0

We get rid of parentheses

-3x+3x-5+5=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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