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2x+5((5-3x)/4)=2
We move all terms to the left:
2x+5((5-3x)/4)-(2)=0
We add all the numbers together, and all the variables
2x+5((-3x+5)/4)-2=0
We multiply all the terms by the denominator
2x*4)+5((-3x+5)-2*4)=0
We add all the numbers together, and all the variables
2x*4)+5((-3x+5)=0
Wy multiply elements
8x^2=0
a = 8; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·8·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{16}=0$
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