2x+4x-8=2(3x-4)

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Solution for 2x+4x-8=2(3x-4) equation: 



2x+4x-8=2(3x-4)

We move all terms to the left:

2x+4x-8-(2(3x-4))=0

We add all the numbers together, and all the variables

6x-(2(3x-4))-8=0



We calculate terms in parentheses: -(2(3x-4)), so:

2(3x-4)

We multiply parentheses

6x-8

Back to the equation:

-(6x-8)



We get rid of parentheses

6x-6x+8-8=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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